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x^2+15x-60=0
a = 1; b = 15; c = -60;
Δ = b2-4ac
Δ = 152-4·1·(-60)
Δ = 465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{465}}{2*1}=\frac{-15-\sqrt{465}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{465}}{2*1}=\frac{-15+\sqrt{465}}{2} $
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